Paper Set

2022

2022 AMC12 Paper & Solutions Pick Paper A

First in-person exam since pandemic, 25 solutions. Number theory features Chinese Remainder Theorem variant.

Sample Problems Download PDF

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25 Questions

75 Minutes

Max Score 150

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Exam Overview

This exam emphasizes number theory. Overall difficulty is moderate.

DDifficulty

EasyQ1-10
MediumQ11-20
HardQ21-25

TTopics

Algebra35%

Geometry30%

Number Theory20%

Combinatorics15%

AAwards

AIME Qualification

AIME Qualification (Top 2.5%)

95+

Honor Roll

Honor Roll (Top 5%)

81+

Achievement Roll

Grade 10 and below

64+

Sample Problems

2022 AMC12 Sample Problems (12 questions)

Sample reference problems by difficulty — click an option to check your answer

Q1EasyPolynomial

If f(x) = 2x² - 5x + 2, find f(4).

A) 10

B) 12

C) 14

D) 16

E) 18

Steps

1f(4) = 2×4² - 5×4 + 2

2= 2×16 - 20 + 2 = 14

Answer: CSubstitute, then exponentiate, multiply/divide, add/subtract

Q3EasyArithmetic Seq

Arithmetic sequence: a₁=5, d=4, find the 14-th term.

A) 45

B) 51

C) 63

D) 57

E) 69

Steps

1aₙ = a₁ + (n-1)d

2a_14 = 5 + 13×4 = 57

Answer: DGeneral term: aₙ=a₁+(n-1)d

Q5EasyExponent

If 3ˣ = 243, find x.

A) 3

B) 4

C) 6

D) 7

E) 5

Steps

1243 = 3^5

2so x = 5

Answer: EConvert to same base, compare exponents

Q7EasyVieta's

Sum of roots of x² - 7x + 6 = 0?

A) 7

B) 3

C) 5

D) 9

E) 11

Steps

1Vieta's:sum of roots = -(-7)/1 = 7

2product of roots = 6

Answer: AFor x²-px+q=0, sum of roots = p

Q10MediumDivisibility

How many integers from 1 to 32 are divisible by 4?

A) 4

B) 8

C) 6

D) 10

E) 12

Steps

1⌊32 / 4⌋ = 8

Answer: BCount divisible by k: ⌊n/k⌋

Q12MediumDiagonals

How many diagonals does a regular 11-gon have?

A) 38

B) 41

C) 44

D) 47

E) 50

Steps

1diagonals = n(n-3)/2

2= 11×8/2 = 44

Answer: Cn-gon diagonals: n(n-3)/2

Q15MediumCombination

Compute C(8, 3).

A) 44

B) 50

C) 62

D) 56

E) 68

Steps

1C(n,3) = n(n-1)(n-2)/6

2= 8×7×6/6 = 56

Answer: DCombination: C(n,k)=n!/(k!(n-k)!)

Q17MediumPythagorean

Right triangle legs 6 and 8, find the hypotenuse.

A) 6

B) 8

C) 12

D) 14

E) 10

Steps

1c² = 6² + 8² = 36 + 64 = 100

2c = √100 = 10

Answer: EPythagorean theorem a²+b²=c²

Q20HardModular Arith

Find the remainder of 5^5 divided by 7.

A) 3

B) 1

C) 2

D) 4

E) 5

Steps

1compute 5^5 mod 7

2simplify step by step (modular arithmetic)

3=3

Answer: AModular arithmetic simplifies large exponents

Q22HardCompleting Sq

Find the minimum of f(x) = x² - 8x + 20.

A) 0

B) 4

C) 2

D) 6

E) 8

Steps

1complete the square:f(x) = (x - 4)² + 4

2when x = 4 , min at 4

Answer: BCompleting the square for quadratic extrema

Q24HardInclusion-Excl

5 distinct balls into 3 distinct boxes, each ≥1 ball, how many ways?

A) 118

B) 134

C) 150

D) 166

E) 182

Steps

1total 3^5 = 243

2subtract empty boxes: -C(3,1)×2^5 = -96

3add back 2 empty boxes: +C(3,2)×1 = +3

4total 243 - 96 + 3 = 150

Answer: CInclusion-exclusion handles 'at least'

Q25HardLaw of Cosines

In △ABC, a=6, b=7, cos C=1/2, find c².

A) 33

B) 38

C) 48

D) 43

E) 53

Steps

1Law of cosines c² = a² + b² - 2ab·cos C

2= 36 + 49 - 42 = 43

Answer: DLaw of cosines is key for solving triangles

Q1EasyPolynomial

If f(x) = 2x² - 7x + 2, find f(4).

A) 2

B) 4

C) 6

D) 8

E) 10

Steps

1f(4) = 2×4² - 7×4 + 2

2= 2×16 - 28 + 2 = 6

Answer: CSubstitute, then exponentiate, multiply/divide, add/subtract

Q3EasyArithmetic Seq

Arithmetic sequence: a₁=7, d=4, find the 14-th term.

A) 47

B) 53

C) 65

D) 59

E) 71

Steps

1aₙ = a₁ + (n-1)d

2a_14 = 7 + 13×4 = 59

Answer: DGeneral term: aₙ=a₁+(n-1)d

Q5EasyExponent

If 3ˣ = 243, find x.

A) 3

B) 4

C) 6

D) 7

E) 5

Steps

1243 = 3^5

2so x = 5

Answer: EConvert to same base, compare exponents

Q7EasyVieta's

Sum of roots of x² - 9x + 6 = 0?

A) 9

B) 5

C) 7

D) 11

E) 13

Steps

1Vieta's:sum of roots = -(-9)/1 = 9

2product of roots = 6

Answer: AFor x²-px+q=0, sum of roots = p

Q10MediumDivisibility

How many integers from 1 to 34 are divisible by 4?

A) 4

B) 8

C) 6

D) 10

E) 12

Steps

1⌊34 / 4⌋ = 8

Answer: BCount divisible by k: ⌊n/k⌋

Q12MediumDiagonals

How many diagonals does a regular 13-gon have?

A) 59

B) 62

C) 65

D) 68

E) 71

Steps

1diagonals = n(n-3)/2

2= 13×10/2 = 65

Answer: Cn-gon diagonals: n(n-3)/2

Q15MediumCombination

Compute C(10, 3).

A) 94

B) 107

C) 133

D) 120

E) 146

Steps

1C(n,3) = n(n-1)(n-2)/6

2= 10×9×8/6 = 120

Answer: DCombination: C(n,k)=n!/(k!(n-k)!)

Q17MediumPythagorean

Right triangle legs 7 and 24, find the hypotenuse.

A) 21

B) 23

C) 27

D) 29

E) 25

Steps

1c² = 7² + 24² = 49 + 576 = 625

2c = √625 = 25

Answer: EPythagorean theorem a²+b²=c²

Q20HardModular Arith

Find the remainder of 5^5 divided by 7.

A) 3

B) 1

C) 2

D) 4

E) 5

Steps

1compute 5^5 mod 7

2simplify step by step (modular arithmetic)

3=3

Answer: AModular arithmetic simplifies large exponents

Q22HardCompleting Sq

Find the minimum of f(x) = x² - 8x + 22.

A) 2

B) 6

C) 4

D) 8

E) 10

Steps

1complete the square:f(x) = (x - 4)² + 6

2when x = 4 , min at 6

Answer: BCompleting the square for quadratic extrema

Q24HardInclusion-Excl

5 distinct balls into 3 distinct boxes, each ≥1 ball, how many ways?

A) 118

B) 134

C) 150

D) 166

E) 182

Steps

1total 3^5 = 243

2subtract empty boxes: -C(3,1)×2^5 = -96

3add back 2 empty boxes: +C(3,2)×1 = +3

4total 243 - 96 + 3 = 150

Answer: CInclusion-exclusion handles 'at least'

Q25HardLaw of Cosines

In △ABC, a=8, b=7, cos C=1/2, find c².

A) 45

B) 51

C) 63

D) 57

E) 69

Steps

1Law of cosines c² = a² + b² - 2ab·cos C

2= 64 + 49 - 56 = 57

Answer: DLaw of cosines is key for solving triangles

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2022 AMC12 Sample Problems (12 questions)

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